( x + 1 )( x + 2 ) + 1/4
= (1/4)[ ( 2x + 2 )( 2x + 4 ) + 1 ]
= (1/4)[ ( 2x + 3 - 1 )( 2x + 3 + 1 ) + 1 ]
= (1/4)[ ( 2x + 3 )” - 1” + 1” ]
= (1/4)( 2x + 3 )”
或者
= x” + 2x + x + 2 + 1/4
= x” + 3x + 2 + 1/4
= (1/4)[ 4x” + 12x + 8 + 1 ]
= (1/4)[ (2x)” + 3(4x) + 9 ]
= (1/4)( 2x + 3 )”
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