利用定积分的换元法计算积分,题目如图,求帮助!

2025-05-19 07:47:01
推荐回答(1个)
回答1:

x=sint
dx=costdt
原式=∫(0,π/2)√(1-sin²t)³dsint
=∫(0,π/2)cos³t·costdt
=∫(0,π/2)cos^4tdt
=3/4×1/2×π/2
=3π/8